Using transform file transform1:

FF = sprintf("%.1f", $x*1.9438)
NN = int($x*12.5 + .5)

and then executing bufrdump on the same BUFR SYNOP file as in the previous example with options --param param1 --csv --filter1 --transform transform1 produced this output:

wmonr,FF,NN
01278,0.0,88
94120,14.0,13
94132,0.0,13
94150,11.1,63
94238,6.0,88
94326,11.1,100
94327,8.9,100
94462,15.9,13
95322,11.1,100
...